Answers for "java how to write generic interface"

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generics Interface in java

/*Sometimes we don’t want the whole class to be parameterized, in that case, we can create java generics method. Since the constructor is a special kind of method, we can use generics type in constructors too.

Here is a class showing an example of a java generic method.

Notice the isEqual method signature showing syntax to use generics type in methods. Also, notice how to use these methods in our java program. We can specify type while calling these methods or we can invoke them like a normal method. Java compiler is smart enough to determine the type of variable to be used, this facility is called type inference.*/


package com.journaldev.generics;

public class GenericsMethods {

	//Java Generic Method
	public static <T> boolean isEqual(GenericsType<T> g1, GenericsType<T> g2){
		return g1.get().equals(g2.get());
	}
	
	public static void main(String args[]){
		GenericsType<String> g1 = new GenericsType<>();
		g1.set("Pankaj");
		
		GenericsType<String> g2 = new GenericsType<>();
		g2.set("Pankaj");
		
		boolean isEqual = GenericsMethods.<String>isEqual(g1, g2);
		//above statement can be written simply as
		isEqual = GenericsMethods.isEqual(g1, g2);
		//This feature, known as type inference, allows you to invoke a generic method as an ordinary method, without specifying a type between angle brackets.
		//Compiler will infer the type that is needed
	}
}
Posted by: Guest on December-06-2020
0

generics Interface in java

/*We know that Java inheritance allows us to assign a variable A to another variable B if A is subclass of B. So we might think that any generic type of A can be assigned to generic type of B, but it’s not the case. Let’s see this with a simple program.

We are not allowed to assign MyClass<String> variable to MyClass<Object> variable because they are not related, in fact MyClass<T> parent is Object.*/
package com.journaldev.generics;

public class GenericsInheritance {

	public static void main(String[] args) {
		String str = "abc";
		Object obj = new Object();
		obj=str; // works because String is-a Object, inheritance in java
		
		MyClass<String> myClass1 = new MyClass<String>();
		MyClass<Object> myClass2 = new MyClass<Object>();
		//myClass2=myClass1; // compilation error since MyClass<String> is not a MyClass<Object>
		obj = myClass1; // MyClass<T> parent is Object
	}
	
	public static class MyClass<T>{}

}
Posted by: Guest on December-06-2020

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