Answers for "java.util.random"

90

random java

import java.util.Random;

Random rand = new Random();

// Obtain a number between [0 - 49].
int n = rand.nextInt(50);

// Add 1 to the result to get a number from the required range
// (i.e., [1 - 50]).
n += 1;
Posted by: Guest on March-09-2020
2

java random

import java.util.Random;
//If there is a need to reproduce the same sequence of random numbers, 
//we have to specify a seed to the constructor, like 100000
Random random = new Random(100000);    //using a seed
System.out.println(random.nextInt(5)); // print one random 0, 1, 2, 3, 4
System.out.println(random.nextInt(5));
Posted by: Guest on October-17-2021
6

java math.random

int rand = (int)(Math.random() * range) + min;
Posted by: Guest on February-04-2021
3

float random class java

import java.util.Random;
public class Example {
   public static void main(String[] args) {
      Random rd = new Random(); // creating Random object
      System.out.println(rd.nextFloat()); // displaying a random float value between 0.0 and 1.0
   }
}
Posted by: Guest on July-20-2020
13

random java

import java.util.Random();
Random <name> = new Random();
<variable> = <name>.nextInt(<excuslive top limit>);
Posted by: Guest on December-28-2019
2

java random seed

Random rand = new Random(System.currentTimeMillis());
Posted by: Guest on May-21-2020

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