Answers for "java random number between"

90

java random number

import java.util.Random;

Random rand = new Random();

// Obtain a number between [0 - 49].
int n = rand.nextInt(50);

// Add 1 to the result to get a number from the required range
// (i.e., [1 - 50]).
n += 1;
Posted by: Guest on March-09-2020
20

java random numbers in specific range

import java.util.Random;

Random rand = new Random();
int random_integer = rand.nextInt(upperbound-lowerbound) + lowerbound;
Posted by: Guest on May-21-2020
10

random number in range java

(int)(Math.random() * ((max - min) + 1)) + min
Copy
Posted by: Guest on March-21-2020
1

java random number between 1 and 10

/* First Method */
int random = (int) (Math.random() * 100 + 1); /* Random number between 1 and 100*/
int random = (int) (Math.random() * 65 + 1); /* Random number between 1 and 65*/
/* Second Method */
import java.util.Random;
Random randnumber = new Random();
int number = randnumber.nextInt(100); /* between 1 and 100*/
system.out.println(number);
Posted by: Guest on June-17-2021
0

random between two numbers java

Random r = new Random();
int low = 10;
int high = 100;
int result = r.nextInt(high-low) + low;
Posted by: Guest on April-24-2021
1

how to get random number in java in range

package com.mkyong.example.test;

import java.util.Random;

public class TestRandom {

    public static void main(String[] args) {

        for (int i = 0; i < 10; i++) {
            System.out.println(getRandomNumberInRange(5, 10));
        }

    }

    private static int getRandomNumberInRange(int min, int max) {

        if (min >= max) {
            throw new IllegalArgumentException("max must be greater than min");
        }

        Random r = new Random();
        return r.nextInt((max - min) + 1) + min;
    }

}
Posted by: Guest on January-20-2021

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