Answers for "java exception to find leap year"

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Java program to find if given year is leap year

import java.util.Scanner;
public class LeapYearDemo
{
   public static void main(String[] args)
   {
      Scanner sc = new Scanner(System.in);
      System.out.println("Please enter any year: ");
      int year = sc.nextInt();
      boolean temp = false;
      if(year % 400 == 0)
      {
         temp = true;
      }
      else if(year % 100 == 0)
      {
         temp = false;
      }
      else if(year % 4 == 0)
      {
         temp = true;
      }
      else
      {
         temp = false;
      }
      if(temp)
      {
         System.out.println("Year " + year + " is a Leap Year");
      }
      else
      {
         System.out.println("Year " + year + " is not a Leap Year");
      }
      sc.close();
   }
}
Posted by: Guest on December-29-2020

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