Answers for "random number generator in java within a range using math.random"

0

could not be opened in append mode: failed to open stream: Permission denied

chmod -R 775 storage
chmod -R 775 bootstrap/cache
Posted by: Guest on November-30-2020
-1

The stream or file "/storage/logs/laravel.log" could not be opened in append mode: failed to open stream: Permission denied

chmod 777 -R storage bootstrap/cache
Posted by: Guest on June-16-2021
0

could not be opened in append mode: failed to open stream: Permission denied

sudo chown -R $USER:www-data storage
sudo chown -R $USER:www-data bootstrap/cache
Posted by: Guest on November-30-2020
0

could not be opened in append mode failed to open stream permission denied

Reference link if giving a permission doesn't solved your issue
https://www.digitalocean.com/community/questions/the-stream-or-file-var-www-html-myscipt-storage-logs-laravel-log-could-not-be-opened-failed-to-open-stream-permission-denied
Posted by: Guest on October-08-2020
1

how to get random number in java in range

package com.mkyong.example.test;

import java.util.Random;

public class TestRandom {

    public static void main(String[] args) {

        for (int i = 0; i < 10; i++) {
            System.out.println(getRandomNumberInRange(5, 10));
        }

    }

    private static int getRandomNumberInRange(int min, int max) {

        if (min >= max) {
            throw new IllegalArgumentException("max must be greater than min");
        }

        Random r = new Random();
        return r.nextInt((max - min) + 1) + min;
    }

}
Posted by: Guest on January-20-2021
12

java random usage

import java.util.Random;

Random rndm = new Random();
int mnmbr = 10;

int rndNumber = rndm.nextInt(mnumber) + 1;

System.out.println(rndNumber);
Posted by: Guest on October-31-2020

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