Answers for "java anagrams"

how to find two strings are anagrams in java

import java.util.Arrays;  
   
public class AnagramString {  
    static void isAnagram(String str1, String str2) {  
        String s1 = str1.replaceAll("\\s", "");  
        String s2 = str2.replaceAll("\\s", "");  
        boolean status = true;  
        if (s1.length() != s2.length()) {  
            status = false;  
        } else {  
            char[] ArrayS1 = s1.toLowerCase().toCharArray();  
            char[] ArrayS2 = s2.toLowerCase().toCharArray();  
            Arrays.sort(ArrayS1);  
            Arrays.sort(ArrayS2);  
            status = Arrays.equals(ArrayS1, ArrayS2);  
        }  
        if (status) {  
            System.out.println(s1 + " and " + s2 + " are anagrams");  
        } else {  
            System.out.println(s1 + " and " + s2 + " are not anagrams");  
        }  
    }  
   
    public static void main(String[] args) {  
        isAnagram("Keep", "Peek");  
        isAnagram("Mother In Law", "Hitler Woman");  
    }  
}  
/*OUTPUT
*Keep and Peek are anagrams
*MotherInLaw and HitlerWoman are anagrams
*/

java anagrams

static boolean isAnagram(String a, String b) {
        
        String sortedA = "";
        Object[] aArr = a.toLowerCase().chars().sorted().mapToObj(i -> (char) i).toArray();
        for (Object o: aArr) {
            sortedA = sortedA.concat(o.toString());
        }
        
        
        String sortedB = "";
        Object[] bArr = b.toLowerCase().chars().sorted().mapToObj(i -> (char) i).toArray();
        for (Object o: bArr) {
            sortedB = sortedB.concat(o.toString());
        }
        
        if(sortedA.equals(sortedB))    
            return true;
        else
            return false;    
    }