Answers for "List - shorting a list"

List - shorting a list

List<Integer> numbers = new ArrayList<>(List.of(6, 5, 8, 3));
Collections.sort(numbers);

// Figyelembe veszi az ékezeteket
List<String> names = new ArrayList<>(List.of("Benjámin", "Áron", "József", "Arnold"));
Collections.sort(names, Collator.getInstance(new Locale("hu", "HU")));

List<Employee> employees = new ArrayList<>(List.of(
        new Employee("John Doe", 1980),
        new Employee("Jack Doe", 1970)));

// Év vagy név szeretnénk rendezni
Collections.sort(employees, new Comparator<Employee>() {
    @Override
    public int compare(Employee o1, Employee o2) {
        // return o1.getYearOfBirth() - o2.getYearOfBirth();
        return o1.getName().compareTo(o2.getName());
    }
});