java ordenar los valores de un array de menor a mayor
public static void main(String[] args) {
int [] a = {7,2,4,8,3,9,1,5,10,6};
int temporal = 0;
for (int i = 0; i < a.length; i++) {
for (int j = 1; j < (a.length - i); j++) {
if (a[j - 1] > a[j]) {
temporal = a[j - 1];
a[j - 1] = a[j];
a[j] = temporal;
}
}
}
System.out.println(Arrays.toString(a));
}java ordenar los valores de un array de menor a mayor
int a[] = {5,3,2,7,10,1};
for (int x = 0; x < a.length; x++) {
for (int i = 0; i < a.length-x-1; i++) {
if(a[i] < a[i+1]){
int tmp = a[i+1];
a[i+1] = a[i];
a[i] = tmp;
}
}
}java ordenar los valores de un array de menor a mayor
public static void main(String[] args) {
optimizedBubbleSort(new int[]{1,2,4,5,6}); // Iteración 0, array ordenado
optimizedBubbleSort(new int[]{11,2,44,5,16}); // Iteración 2, array ordenado
optimizedBubbleSort(new int[]{0,8,74,5,1}); // Iteración 3, array ordenado
}
private static void optimizedBubbleSort(int [] list){
for(int i =0; i< list.length; i++){
boolean sorted = true; // asumo que para la iteración i el listado es ordenado,
for(int j =0; j< list.length - i - 1; j++){ // en cada iteración los elementos desde la posición (length-i) estan ordenados, por lo tanto solo recorro hasta esa posición
if(list[j] > list[j+1]){
int temp = list[j];
list[j] = list[j+1];
list[j+1] = temp;
sorted = false;
}
}
if(sorted){
System.out.println(String.format("Iteración %s, array ordenado", i));
return;
}
}
}Copyright © 2021 Codeinu
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