Answers for "how to produce random stringid in java"

3

generate random string in java

import java.util.Random;

public class Generator {
	public static String generateRandomPassword(int len) {
		String chars = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijk"
          +"lmnopqrstuvwxyz!@#$%&";
		Random rnd = new Random();
		StringBuilder sb = new StringBuilder(len);
		for (int i = 0; i < len; i++)
			sb.append(chars.charAt(rnd.nextInt(chars.length())));
		return sb.toString();
	}
}
Posted by: Guest on July-16-2020
1

java random string

public static String getRandomString(int size) {
  	// The string that we will return
	String rand = "";
  	// The chars that are used to generate the random string
	String chars = "1234567890-=!@#$%^&*()_+qwertyuiop[]\\QWERTYUIOP{}|asdfghjkl;'ASDFGHJKL:\"zxcvbnm,./ZXCVBNM<>?";
  	// Loop based on the requested size
  	for (int i = 0; i < size; i++) {
      	// Add a random char from the chars string to the rand string
		rand += chars.toCharArray()[new Random().nextInt(chars.length())];
	}
  	// Return the random string
	return rand;
}
Posted by: Guest on May-28-2021

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