Answers for "inorder traversal"

0

inorder

void inorder(Node* root){
    if(root != NULL){
        inorder(root->left);
        cout<<root->data<<" ";
        inorder(root->right);
    }
}
Posted by: Guest on August-01-2021
0

inorder traversal

vector<int> v;
void inorder(TreeNode* root,vector<int> &v)
{
  if(root==NULL)
    return;
  inorder(root->left,v);
  v.push_back(root->val);
  inorder(root->right,v);
}
Posted by: Guest on August-20-2021
0

inorder traversal

class Solution {
    public List<Integer> inorderTraversal(TreeNode root) {
        List<Integer> list = new ArrayList<Integer>();
        return dfs(root, list);
    }
    private List<Integer> dfs(TreeNode root, List<Integer> list)
    {
        if(root == null)
            return list;
        list = dfs(root.left, list);
        list.add(root.val);
        return dfs(root.right,list);
    }
}
Posted by: Guest on July-20-2021
-2

preorder traversal

#include <iostream>
using namespace std;

class node{
public:
    int data;
    node* left;
    node* right;

    node(int d){
        data = d;
        left = NULL;
        right = NULL;
    }
};

node* buildTree(){
    int d;
    cin>>d;

    if(d==-1){
        return NULL;	//to attach a NULL pointer[in case of no child] enter -1
    }
    node * root = new node(d);
    root->left = buildTree();
    root->right = buildTree();
    return root;
}



//REQUIRED FUNCTION: Inorder Traversal


void printIn(node*root){
    if(root==NULL){
        return;
    }
    //Otherwise Left Root Right
    printIn(root->left);
    cout<<root->data<<" ";
    printIn(root->right);
}


int main(){ 
    node* root = buildTree();
    printIn(root);

	return 0;
}

//SAMPLE INPUT TO RUN THE CODE ON ANY ONLINE IDE:
//8 10 1 -1 -1 6 9 -1 -1 7 -1 -1 3 -1 14 13 -1 -1 -1
Posted by: Guest on October-07-2020
-1

tree inorder traversal

hello how are you?
Posted by: Guest on October-09-2021

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