java throw an exception
public static void main(String[] args) {
Scanner kb = new Scanner(System.in);
System.out.println("Enter a number");
try {
double nb1 = kb.nextDouble();
if(nb1<0)
throw new ArithmeticException();
else System.out.println( "result : " + Math.sqrt(nb1) );
} catch (ArithmeticException e) {
System.out.println("You tried an impossible sqrt");
}
}throwing exceptions java
/* In this program we are checking the Student age
* if the student age<12 and weight <40 then our program
* should return that the student is not eligible for registration.
*/
public class ThrowExample {
static void checkEligibilty(int stuage, int stuweight){
if(stuage<12 && stuweight<40) {
throw new ArithmeticException("Student is not eligible for registration");
}
else {
System.out.println("Student Entry is Valid!!");
}
}
public static void main(String args[]){
System.out.println("Welcome to the Registration process!!");
checkEligibilty(10, 39);
System.out.println("Have a nice day..");
}
}java return exception
void testMethod() throws ArithmeticException, ArrayIndexOutOfBoundsException {
// rest of code
}Copyright © 2021 Codeinu
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