java test if a string is a int
public static boolean isInt(String str) {
try {
@SuppressWarnings("unused")
int x = Integer.parseInt(str);
return true; //String is an Integer
} catch (NumberFormatException e) {
return false; //String is not an Integer
}
}java how to check string is number
public static boolean isNumeric(String strNum) {
if (strNum == null) {
return false;
}
try {
double d = Double.parseDouble(strNum);
} catch (NumberFormatException nfe) {
return false;
}
return true;
}how to check if a string has only numbers in java
// Java program for the above approach
// contains only digits
class GFG {
// Function to check if a string
// contains only digits
public static boolean
onlyDigits(String str, int n)
{
// Traverse the string from
// start to end
for (int i = 0; i < n; i++) {
// Check if character is
// digit from 0-9
// then return true
// else false
if (str.charAt(i) >= '0'
&& str.charAt(i) <= '9') {
return true;
}
else {
return false;
}
}
return false;
}
// Driver Code
public static void main(String args[])
{
// Given string str
String str = "1234";
int len = str.length();
// Function Call
System.out.println(onlyDigits(str, len));
}
}determine if is string or int
string str = "3257fg";
for(int i = 0;i < (strlen(str) - 1);i++) {
if((int)str[i] < 10) {
// it is a number, so do some code
} else {
// it is not a number, do something else
}
}Copyright © 2021 Codeinu
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