Answers for "how to sort an arraylist biggest to smallest in java"

java how to find the largest number in an arraylist

List<Integer> myList = new ArrayList<>();

for(int i = 0; i < 10; i++){
    myList.add(i);
}
//gets highest number in the list
int highestNumber = Collections.max(myList);

System.out.Println(highestNumber);

//output: 9

how to find the smallest numbers in an arraylist java

import java.util.ArrayList;
 
import java.util.Scanner;
 
public class IndexOfSmallest {
 
    public static void main(String[] args) {
 
        Scanner scanner = new Scanner(System.in);
      
        ArrayList<Integer> list = new ArrayList<>();
 
        while (true) {
 
            int input = Integer.valueOf(scanner.nextLine());
 
            if (input == 9999) {
 
                break;
 
            }
 
            list.add(input);
 
        }
 
        System.out.println("");
 
        int smallest = list.get(0);
 
        int index = 0;
 
        while (index < list.size()) {
 
            if (list.get(index) < smallest) {
 
                smallest = list.get(index);
 
            }
 
            index++;
 
        }
 
        System.out.println("Smallest number: " + smallest);
 
        index = 0;
 
        while (index < list.size()) {
 
            if (list.get(index) == smallest) {
 
                System.out.println("Found at index: " + index);
 
            }
 
            index++;
 
        }
 
    }
 
}