java how to find the largest number in an arraylist
List<Integer> myList = new ArrayList<>();
for(int i = 0; i < 10; i++){
myList.add(i);
}
//gets highest number in the list
int highestNumber = Collections.max(myList);
System.out.Println(highestNumber);
//output: 9how to find the smallest numbers in an arraylist java
import java.util.ArrayList;
import java.util.Scanner;
public class IndexOfSmallest {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
ArrayList<Integer> list = new ArrayList<>();
while (true) {
int input = Integer.valueOf(scanner.nextLine());
if (input == 9999) {
break;
}
list.add(input);
}
System.out.println("");
int smallest = list.get(0);
int index = 0;
while (index < list.size()) {
if (list.get(index) < smallest) {
smallest = list.get(index);
}
index++;
}
System.out.println("Smallest number: " + smallest);
index = 0;
while (index < list.size()) {
if (list.get(index) == smallest) {
System.out.println("Found at index: " + index);
}
index++;
}
}
}Copyright © 2021 Codeinu
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