java how to find the largest number in an arraylist
List<Integer> myList = new ArrayList<>();
for(int i = 0; i < 10; i++){
myList.add(i);
}
//gets highest number in the list
int highestNumber = Collections.max(myList);
System.out.Println(highestNumber);
//output: 9find max integer in arraylist java
List<Integer> list = new ArrayList<Integer>();
Collections.max(list)java arraylist max length
The theoretical limit for ArrayList capacity is Integer. MAX_VALUE, a.k.a. 2^31 - 1, a.k.a. 2,147,483,647. But you'll probably get an OutOfMemoryError long before that time because, well, you run out of memoryjava find largest number in list
int max = (The provided List).stream().max((i1,i2)->(i1>i2)?1:(i1<i2)-1:0).get();Copyright © 2021 Codeinu
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