min of an array java
public int min()
{
int min = elementData[0];
for (int i = 1; i < size; i++)
{
if (elementData[i] < min)
{
min = elementData[i];
}
}
return min;
}find min in array java
private static int findMin(int[] array) {
int min = array[0];
for(int i=1;i<array.length;i++) {
if(min > array[i]) {
min = array[i];
}
}
return min;
}find minimum number in array java
public class MinimumNumber{
public static void main(String[] args){
int[] arr=new int[]{2,3,4,1};
int min=arr[0];
for(int i=0;i<arr.length;i++){
if(arr[i]<min){
min=arr[i];
}
}
System.out.println("Minimum Number in array:"+min);
}
}java 8 find min value in array
package com.concerned.crossbill;
import java.util.Arrays;
public class Foo {
public int getMin(int[] numbers) {
return Arrays.stream(numbers).min().getAsInt();
}
}
// test class
import org.junit.Test;
import static org.junit.Assert.assertEquals;
import com.concerned.crossbill.Foo;
public class FooTest {
public void testGetMin() {
int[] numbers = new int[]{12, 10, 31, 30, 23, 4, 5, 5, 5, 5, 10, 40};
Foo foo = new Foo();
int result = foo.getMin(numbers);
int expResult = 4;
assertEquals(expResult, result);
}
}min array number in java
Integer[] num = { 2, 4, 7, 5, 9 };
// using Collections.min() to find minimum element
// using only 1 line.
int min1 = Collections.min(Arrays.asList(num));
// using Collections.max() to find maximum element
// using only 1 line.
int max1 = Collections.max(Arrays.asList(num));
System.out.println(min1); // 2
System.out.println(max1); // 9Copyright © 2021 Codeinu
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