max in array java
// Initializing array of integers
Integer[] num = { 2, 4, 7, 5, 9 };
// using Collections.min() to find minimum element
// using only 1 line.
int min = Collections.min(Arrays.asList(num));
// using Collections.max() to find maximum element
// using only 1 line.
int max = Collections.max(Arrays.asList(num));java max array
public static String max(String[] arr) {
String result = arr[0];
for (int i = 1; i < arr.length; ++i) {
if (result.compareTo(arr[i]) < 0) result = arr[i];
}
return result;
}find min in array java
private static int findMin(int[] array) {
int min = array[0];
for(int i=1;i<array.length;i++) {
if(min > array[i]) {
min = array[i];
}
}
return min;
}finding min and max from given number in java
Scanner input = new Scanner(System.in);
// Minimum And Maximum
int count = 0;
int min = 0;
int max = 0;
boolean bugSolved = true;
/* or we can use :
int min = Integer.MAX_VALUE;
int max = Integer.MIN_VALUE;
*/
while (true){
int cnt = count++;
System.out.print("Enter Number #"+(cnt+1)+": ");
boolean isValid = input.hasNextInt();
if(isValid){
int num = input.nextInt();
/* if (bugSolved){
bugSolved = false;
min = num;
max = num;
} # Just remove this condition and
boolean (bugSolved) at the top, if you use
int min = Integer.MAX_VALUE and int max =
Integer.MIN_VALUE */
if (num < min) {
min = num;
}else if (num > max){
max = num;
}
}else{
System.out.println("Invalid input..");
break;
}
input.nextLine();
}
System.out.println("Min Number : " + min);
System.out.println("Max Number : " + max);Copyright © 2021 Codeinu
Forgot your account's password or having trouble logging into your Account? Don't worry, we'll help you to get back your account. Enter your email address and we'll send you a recovery link to reset your password. If you are experiencing problems resetting your password contact us
