Answers for "program to find maximum number in array in java"

3

Java program to find maximum and minimum number without using array

// Java program to find maximum and minimum number without using array
import java.util.Scanner;
public class MaximumMinimumWithoutArray
{
   public static void main(String[] args)
   {
      Scanner sc = new Scanner(System.in);
      System.out.println("Please enter total number: ");
      int numbers = sc.nextInt();
      int maximum = Integer.MIN_VALUE;
      int minimum = Integer.MAX_VALUE;
      System.out.println("Please enter " + numbers + " numbers.");
      for(int a = 0; a < numbers; a++)
      {
         int current = sc.nextInt();
         if(current > maximum)
         {
            maximum = current;
         }
         if(current < minimum)
         {
            minimum = current;
         }
      }
      System.out.println("largest of " + numbers + " numbers is: " + maximum);
      System.out.println("smallest of " + numbers + " numbers is: " + minimum);
      sc.close();
   }
}
Posted by: Guest on February-22-2021
3

how to get the max value of an array java

public static double arrayMax(double[] arr) {
    double max = Double.NEGATIVE_INFINITY;

    for(double cur: arr)
        max = Math.max(max, cur);

    return max;
}
Posted by: Guest on May-10-2020
1

maximum arrays size in java

int arr[] = new int[N];// Maximum Value Of N:2,147,483,647 (max int size)
Posted by: Guest on May-15-2020
0

how to get the max value of an array java

import java.util.Random;

public class Main {

public static void main(String[] args) {
   int a[] = new int [100];
   Random rnd = new Random ();

    for (int i = 0; i< a.length; i++) {
        a[i] = rnd.nextInt(99-0)+0;
        System.out.println(a[i]);
    }

    int max = 0;          

    for (int i = 0; i < a.length; i++) {
        a[i] = max;


        for (int j = i+1; j<a.length; j++) {
            if (a[j] > max) {
               max = a[j];
            }

        }
    }

    System.out.println("Max element: " + max);
}
}
Posted by: Guest on May-10-2020

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