max in array java
// Initializing array of integers
Integer[] num = { 2, 4, 7, 5, 9 };
// using Collections.min() to find minimum element
// using only 1 line.
int min = Collections.min(Arrays.asList(num));
// using Collections.max() to find maximum element
// using only 1 line.
int max = Collections.max(Arrays.asList(num));how to get the max value of an array java
public static double arrayMax(double[] arr) {
double max = Double.NEGATIVE_INFINITY;
for(double cur: arr)
max = Math.max(max, cur);
return max;
}maximum arrays size in java
int arr[] = new int[N];// Maximum Value Of N:2,147,483,647 (max int size)finding min and max from given number in java
Scanner input = new Scanner(System.in);
// Minimum And Maximum
int count = 0;
int min = 0;
int max = 0;
boolean bugSolved = true;
/* or we can use :
int min = Integer.MAX_VALUE;
int max = Integer.MIN_VALUE;
*/
while (true){
int cnt = count++;
System.out.print("Enter Number #"+(cnt+1)+": ");
boolean isValid = input.hasNextInt();
if(isValid){
int num = input.nextInt();
/* if (bugSolved){
bugSolved = false;
min = num;
max = num;
} # Just remove this condition and
boolean (bugSolved) at the top, if you use
int min = Integer.MAX_VALUE and int max =
Integer.MIN_VALUE */
if (num < min) {
min = num;
}else if (num > max){
max = num;
}
}else{
System.out.println("Invalid input..");
break;
}
input.nextLine();
}
System.out.println("Min Number : " + min);
System.out.println("Max Number : " + max);Copyright © 2021 Codeinu
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