max value in array javascript
// For large data, it's better to use reduce. Supose arr has a large data in this case:
const arr = [1, 5, 3, 5, 2];
const max = arr.reduce((a, b) => { return Math.max(a, b) });
// For arrays with relatively few elements you can use apply:
const max = Math.max.apply(null, arr);
// or spread operator:
const max = Math.max(...arr);max in array java
// Initializing array of integers
Integer[] num = { 2, 4, 7, 5, 9 };
// using Collections.min() to find minimum element
// using only 1 line.
int min = Collections.min(Arrays.asList(num));
// using Collections.max() to find maximum element
// using only 1 line.
int max = Collections.max(Arrays.asList(num));find maximum number in array
#include <stdio.h>
int main() {
int i, n;
float arr[100];
printf("Enter the number of elements (1 to 100): ");
scanf("%d", &n);
for (i = 0; i < n; ++i) {
printf("Enter number%d: ", i + 1);
scanf("%f", &arr[i]);
}
// storing the largest number to arr[0]
for (i = 1; i < n; ++i) {
if (arr[0] < arr[i])
arr[0] = arr[i];
}
printf("Largest element = %.2f", arr[0]);
return 0;
}get largest number in array javascript
const array1 = [1, 3, 2];
Math.max(...array1);
// expected output: 3javascript get array min and max
//get min/max value of arrays
function getArrayMax(array){
return Math.max.apply(null, array);
}
function getArrayMin(array){
return Math.min.apply(null, array);
}
var ages=[11, 54, 32, 92];
var maxAge=getArrayMax(ages); //92
var minAge=getArrayMin(ages); //11how to find max in array
int[] a = new int[] { 20, 30, 50, 4, 71, 100};
int max = a[0];
for(int i = 1; i < a.length;i++)
{
if(a[i] > max)
{
max = a[i];
}
}
System.out.println("The Given Array Element is:");
for(int i = 0; i < a.length;i++)
{
System.out.println(a[i]);
}
System.out.println("From The Array Element Largest Number is:" + max);Copyright © 2021 Codeinu
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