Answers for ""main" java.lang.numberformatexception: for input string: """

0

exception in thread "main" java.lang.numberformatexception: for input string: ""

int number = 0; // or any application default value
try {
	number = Integer.parseInt(input);
} catch (NumberFormatException nfe) {
	// do whatever you need to do if you get an invalid number
	// you can put the try catch in a loop and keep asking for a 
    // value until you don't get a valid one
    
  	// If you want to use the default value in case of an
    // invalid number you can do nothing in here
}
Posted by: Guest on May-19-2021
0

java.lang.NumberFormatException: For input string: ""

"N/A" is not an integer. It must throw NumberFormatException if you try to parse it to an integer.

Check before parsing or handle Exception properly.

Exception Handling

try{
    int i = Integer.parseInt(input);
} catch(NumberFormatException ex){ // handle your exception
    ...
}
Posted by: Guest on March-05-2021

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