Answers for "java.lang.NumberFormatException: For input string: """

java.lang.NumberFormatException: For input string: ""

"N/A" is not an integer. It must throw NumberFormatException if you try to parse it to an integer.

Check before parsing or handle Exception properly.

Exception Handling

try{
    int i = Integer.parseInt(input);
} catch(NumberFormatException ex){ // handle your exception
    ...
}

java.lang.NumberFormatException: For input string: "0.01""

Long.valueOf("0.01"");