Answers for "bubble sort numbers"

4

bubble sort in java

public static void bubbleSort(int arr[])
{
	for (int i = 0; i < arr.length; i++) //number of passes
    {
		//keeps track of positions per pass      
    	for (int j = 0; j < (arr.length - 1 - i); j++) //Think you can add a -i to remove uneeded comparisons 
        {
          	//if left value is great than right value 
        	if (arr[j] > arr[j + 1])
            {
              	//swap values
            	int temp = arr[j];
              	arr[j] = arr[j + 1];
              	arr[j + 1] = temp; 
            }
        }
    }
}
Posted by: Guest on April-15-2020
3

bubble sort c

#include <bits/stdc++.h> 
using namespace std; 
  
void swap(int *xp, int *yp)  
{  
    int temp = *xp;  
    *xp = *yp;  
    *yp = temp;  
}  
  
// A function to implement bubble sort  
void bubbleSort(int arr[], int n)  
{  
    int i, j;  
    for (i = 0; i < n-1; i++)      
      
    // Last i elements are already in place  
    for (j = 0; j < n-i-1; j++)  
        if (arr[j] > arr[j+1])  
            swap(&arr[j], &arr[j+1]);  
}  
  
/* Function to print an array */
void printArray(int arr[], int size)  
{  
    int i;  
    for (i = 0; i < size; i++)  
        cout << arr[i] << " ";  
    cout << endl;  
}  
  
// Driver code  
int main()  
{  
    int arr[] = {64, 34, 25, 12, 22, 11, 90};  
    int n = sizeof(arr)/sizeof(arr[0]);  
    bubbleSort(arr, n);  
    cout<<"Sorted array: \n";  
    printArray(arr, n);  
    return 0;  
}
Posted by: Guest on July-02-2020
0

bubble sort integers

for (int i = 0; i < n-1; i++) 
            for (int j = 0; j < n-i-1; j++) 
                if (arr[j] > arr[j+1]) 
                { 
                    // swap arr[j+1] and arr[i] 
                    int temp = arr[j]; 
                    arr[j] = arr[j+1]; 
                    arr[j+1] = temp; 
                }
Posted by: Guest on September-01-2020

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