reverse number in java
public class ReverseNumber {
public static void main(String[] args) {
int num = 1234, reversed = 0;
while(num != 0) {
int digit = num % 10;
reversed = reversed * 10 + digit;
num = num / 10;
}
System.out.println("Reversed Number: " + reversed);
}}reverse a number using arithmetic operations
//continue to loop until a value is equal to 0
public class ReverseNum{
public static void main(String[] args {
int a = 543;
int reverse = 0;
while(a!=0){ //itera the process
int digit = a%10; //isolate the last digit number
reverse = digit + (reverse*10); //append last digit to reverse
a=a/10; // remove the last digit from number
}
System.out.println(reverse);
} }print reverse number
void printReverse(int n) {
if (n < 1) return;
cout << n << endl;
printReverse(n - 1);
}
printReverse(10); /// 10 9 8 7 6 5 4 3 2 1Copyright © 2021 Codeinu
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