Answers for "breadth first search java"

1

breadth first search BST java

import java.io.*;
import java.util.*;

class Graph
{
    private int V;                              //number of nodes in the graph
    private LinkedList<Integer> adj[];              //adjacency list
    private Queue<Integer> queue;                   //maintaining a queue
 
    Graph(int v)
    {
        V = v;
        adj = new LinkedList[v];
        for (int i=0; i<v; i++)
        {
            adj[i] = new LinkedList<>();
        }
        queue = new LinkedList<Integer>();
    }

 
    void addEdge(int v,int w)
    {
        adj[v].add(w);                          //adding an edge to the adjacency list (edges are bidirectional in this example)
    }
 
    void BFS(int n)
    {

        boolean nodes[] = new boolean[V];       //initialize boolean array for holding the data
        int a = 0;
 
        nodes[n]=true;                  
        queue.add(n);                   //root node is added to the top of the queue
 
        while (queue.size() != 0)
        {
            n = queue.poll();             //remove the top element of the queue
            System.out.print(n+" ");           //print the top element of the queue
 
            for (int i = 0; i < adj[n].size(); i++)  //iterate through the linked list and push all neighbors into queue
            {
                a = adj[n].get(i);
                if (!nodes[a])                    //only insert nodes into queue if they have not been explored already
                {
                    nodes[a] = true;
                    queue.add(a);
                }
            }  
        }
    }

    public static void main(String args[])
    {
        Graph graph = new Graph(6);
 
        graph.addEdge(0, 1);
        graph.addEdge(0, 3);
        graph.addEdge(0, 4);
        graph.addEdge(4, 5);
        graph.addEdge(3, 5);
        graph.addEdge(1, 2);
        graph.addEdge(1, 0);
        graph.addEdge(2, 1);
        graph.addEdge(4, 1);
        graph.addEdge(3, 1);
        graph.addEdge(5, 4);
        graph.addEdge(5, 3);
 
        System.out.println("The Breadth First Traversal of the graph is as follows :");
 
        graph.BFS(0);
    }
}
Posted by: Guest on October-13-2021
0

BFS in c++

#include<iostream>
#include <list>
 
using namespace std;
 


class Graph
{
    int V;   
 
  
    list<int> *adj;   
public:
    Graph(int V);  
 
    
    void addEdge(int v, int w); 
 
    
    void BFS(int s);  
};
 
Graph::Graph(int V)
{
    this->V = V;
    adj = new list<int>[V];
}
 
void Graph::addEdge(int v, int w)
{
    adj[v].push_back(w); 
}
 
void Graph::BFS(int s)
{
  
    bool *visited = new bool[V];
    for(int i = 0; i < V; i++)
        visited[i] = false;
 
   
    list<int> queue;
 
   
    visited[s] = true;
    queue.push_back(s);
 
   
    list<int>::iterator i;
 
    while(!queue.empty())
    {
       
        s = queue.front();
        cout << s << " ";
        queue.pop_front();
 
      
        for (i = adj[s].begin(); i != adj[s].end(); ++i)
        {
            if (!visited[*i])
            {
                visited[*i] = true;
                queue.push_back(*i);
            }
        }
    }
}
 

int main()
{
    
    Graph g(4);
    g.addEdge(0, 1);
    g.addEdge(0, 2);
    g.addEdge(1, 2);
    g.addEdge(2, 0);
    g.addEdge(2, 3);
    g.addEdge(3, 3);
 
    cout << "Following is Breadth First Traversal "
         << "(starting from vertex 2) \n";
    g.BFS(2);
 
    return 0;
}
Posted by: Guest on December-08-2020

Code answers related to "breadth first search java"

Code answers related to "Java"

Java Answers by Framework

Browse Popular Code Answers by Language