Answers for "JSON.stringify()"

6

json stringify pretty

JSON.stringify(jsonobj,null,'\t')
Posted by: Guest on January-31-2020
10

node json stringify

let data = {
  name: "John Smith",
  age: 30,
  hobbies: ["Programming", "Video Games"]
};

// {name:"John Smith",age:30,hobbies:["Programming","Video Games"]}
let miny = JSON.stringify(data);

// The 4 parameter signifys 4 spaces. You can also use "\t".
/* {
 *     name: "John Smith",
 *     age: 30,
 *     ...
 */
let pretty = JSON.stringify(data, null, 4);
Posted by: Guest on June-20-2020
1

javascript stringify an object

console.log(JSON.stringify({ x: 5, y: 6 }));
// expected output: "{"x":5,"y":6}"

console.log(JSON.stringify([new Number(3), new String('false'), new Boolean(false)]));
// expected output: "[3,"false",false]"

console.log(JSON.stringify({ x: [10, undefined, function(){}, Symbol('')] }));
// expected output: "{"x":[10,null,null,null]}"

console.log(JSON.stringify(new Date(2006, 0, 2, 15, 4, 5)));
// expected output: ""2006-01-02T15:04:05.000Z""
Posted by: Guest on September-16-2020
41

object to json javascript

var person={"first_name":"Tony","last_name":"Hawk","age":31};
var personJSONString=JSON.stringify(person);
Posted by: Guest on July-23-2019
4

convert json.stringify to array in javascript

const myObj = {
  name: 'Skip',
  age: 2,
  favoriteFood: 'Steak'
};

const myObjStr = JSON.stringify(myObj);

console.log(myObjStr);
// "{"name":"Skip","age":2,"favoriteFood":"Steak"}"

console.log(JSON.parse(myObjStr));
// Object {name:"Skip",age:2,favoriteFood:"Steak"}
Posted by: Guest on May-21-2020
2

json.stringify parameters

var person={"first_name":"Tony","last_name":"Hawk","age":31};
console.log(JSON.stringify(person , null , 4)); 
//Output:
> "{
    "first_name": "Tony",
    "last_name": "Hawk",
    "age": 31
}"
Posted by: Guest on November-12-2020

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