Answers for "aexecute function after time js"

1

javascipt delay

function sleep(ms) {
  return new Promise(resolve => setTimeout(resolve, ms));
}

console.log("Hello");
sleep(2000).then(() => { console.log("World!"); });
Posted by: Guest on May-16-2020
1

javascipt delay

async function delay(delayInms) {
      return new Promise(resolve  => {
        setTimeout(() => {
          resolve(2);
        }, delayInms);
      });
    }
    async function sample() {
      console.log('a');
      console.log('waiting...')
      let delayres = await delay(3000);
      console.log('b');
    }
    sample();
Posted by: Guest on May-16-2020

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