filter array with unique objects javascript
const array =
[
{ "name": "Joe", "age": 17 },
{ "name": "Bob", "age": 17 },
{ "name": "Carl", "age": 35 }
]
const key = 'age';
const arrayUniqueByKey = [...new Map(array.map(item =>
[item[key], item])).values()];
console.log(arrayUniqueByKey);
/*OUTPUT
[
{ "name": "Bob", "age": 17 },
{ "name": "Carl", "age": 35 }
]
*/
// Note: this will pick the last duplicated item in the list.unique array javascript es6 Map
const data = [
{ group: 'A', name: 'SD' },
{ group: 'B', name: 'FI' },
{ group: 'A', name: 'MM' },
{ group: 'B', name: 'CO'}
];
const unique = [...new Set(data.map(item => item.group))]; // [ 'A', 'B']javascript map return array with distinc values
//ES6
let array = [
{ "name": "Joe", "age": 17 },
{ "name": "Bob", "age": 17 },
{ "name": "Carl", "age": 35 }
];
array.map(item => item.age)
.filter((value, index, self) => self.indexOf(value) === index)
> [17, 35]javascript get unique values from key
const unique = [...new Set(array.map(item => item.age))];create unique set of array of objects
function unique(array, propertyName) {
return array.filter((e, i) => array.findIndex(a => a[propertyName] === e[propertyName]) === i);
}javascript find unique values in array of objects
var flags = [], output = [], l = array.length, i;
for( i=0; i<l; i++) {
if( flags[array[i].age]) continue;
flags[array[i].age] = true;
output.push(array[i].age);
}Copyright © 2021 Codeinu
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