javascript array remove element
var colors = ["red","blue","car","green"];
var carIndex = colors.indexOf("car");//get "car" index
//remove car from the colors array
colors.splice(carIndex, 1); // colors = ["red","blue","green"]javascript array remove element
var colors = ["red","blue","car","green"];
var carIndex = colors.indexOf("car");//get "car" index
//remove car from the colors array
colors.splice(carIndex, 1); // colors = ["red","blue","green"]remove the items in array which are present in another javascript
var myArray = [
{name: 'deepak', place: 'bangalore'},
{name: 'chirag', place: 'bangalore'},
{name: 'alok', place: 'berhampur'},
{name: 'chandan', place: 'mumbai'}
];
var toRemove = [
{name: 'deepak', place: 'bangalore'},
{name: 'alok', place: 'berhampur'}
];
myArray = myArray.filter(ar => !toRemove.find(rm => (rm.name === ar.name && ar.place === rm.place) ))js array delete specific element
var arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 0];
var removed = arr.splice(2,2);
/*
removed === [3, 4]
arr === [1, 2, 5, 6, 7, 8, 9, 0]
*/js remove several elements from array
var ar = [1, 2, 3, 4, 5, 6];ar.pop(); // returns 6console.log( ar ); // [1, 2, 3, 4, 5]remove an element in array useing another array
Remove an item comparing from other array
const toRemoveMap = toRemove.reduce(
function(memo, item) {
memo[item] = memo[item] || true;
return memo;
},
{} // initialize an empty object
);
const filteredArray = myArray.filter(function (x) {
return toRemoveMap[x];
});
// or, if you want to use ES6-style arrow syntax:
const toRemoveMap = toRemove.reduce((memo, item) => ({
...memo,
[item]: true
}), {});
const filteredArray = myArray.filter(x => toRemoveMap[x.id]);
From <https://stackoverflow.com/questions/19957348/remove-all-elements-contained-in-another-array>Copyright © 2021 Codeinu
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