javascript do arrays intersect
let intersection = arrA.filter(x => arrB.includes(x));javascript do arrays intersect
let intersection = arrA.filter(x => arrB.includes(x));js array intersection object
const arr1 = [{ id: 1 }, { id: 2 }]
const arr2 = [{ id: 1 }, { id: 3 }]
const intersection = arr1.filter(item1 => arr2.some(item2 => item1.id === item2.id))
// intersection => [{ id: 1 }]javascript get intersection of two arrays
function getArraysIntersection(a1,a2){
return a1.filter(function(n) { return a2.indexOf(n) !== -1;});
}
var colors1 = ["red","blue","green"];
var colors2 = ["red","yellow","blue"];
var intersectingColors=getArraysIntersection(colors1, colors2); //["red", "blue"]find intersection between two object arrays javascript
// Generic helper function that can be used for the three operations:
const operation = (list1, list2, isUnion = false) =>
list1.filter(
(set => a => isUnion === set.has(a.userId))(new Set(list2.map(b => b.userId)))
);
// Following functions are to be used:
const inBoth = (list1, list2) => operation(list1, list2, true),
inFirstOnly = operation,
inSecondOnly = (list1, list2) => inFirstOnly(list2, list1);
// Sample data
const list1 = [
{ userId: 1234, userName: 'XYZ' },
{ userId: 1235, userName: 'ABC' },
{ userId: 1236, userName: 'IJKL' },
{ userId: 1237, userName: 'WXYZ' },
{ userId: 1238, userName: 'LMNO' }
];
const list2 = [
{ userId: 1235, userName: 'ABC' },
{ userId: 1236, userName: 'IJKL' },
{ userId: 1252, userName: 'AAAA' }
];
console.log('inBoth:', inBoth(list1, list2));
console.log('inFirstOnly:', inFirstOnly(list1, list2));
console.log('inSecondOnly:', inSecondOnly(list1, list2));Copyright © 2021 Codeinu
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