Answers for "get element from array javascript"

50

javascript find

const inventory = [
  {name: 'apples', quantity: 2},
  {name: 'cherries', quantity: 8}
  {name: 'bananas', quantity: 0},
  {name: 'cherries', quantity: 5}
  {name: 'cherries', quantity: 15}
  
];

const result = inventory.find( ({ name }) => name === 'cherries' );

console.log(result) // { name: 'cherries', quantity: 5 }
Posted by: Guest on July-11-2020
139

javascript array

//create an array like so:
var colors = ["red","blue","green"];

//you can loop through an array like this:
for (var i = 0; i < colors.length; i++) {
    console.log(colors[i]);
}
Posted by: Guest on July-01-2019
12

javascript array.find

const array1 = [5, 12, 8, 130, 44];

const found = array1.find(element => element > 10);

console.log(found);
// expected output: 12
Posted by: Guest on June-01-2020
0

find typescript

const inventory = [
    {name: 'apples', quantity: 2},
    {name: 'bananas', quantity: 0},
    {name: 'cherries', quantity: 5}
];

function findCherries(fruit) { 
    return fruit.name === 'cherries';
}

inventory.find(findCherries); // { name: 'cherries', quantity: 5 }

/* OR */
  inventory.filter(x => x.name === 'bananas')[0]; // { name: 'bananas', quantity:0}  

/* OR */

inventory.find(e => e.name === 'apples'); // { name: 'apples', quantity: 2 }
Posted by: Guest on January-05-2021
10

js array find

var ages = [3, 10, 18, 20];

function checkAdult(age) {
  return age >= 18;
}
/* find() runs the input function agenst all array components
   till the function returns a value
*/
ages.find(checkAdult);
Posted by: Guest on April-09-2020
1

javascript get array value

var array = []
array[0] = "hi"
array[1] = "dude"
var done = false
while (done == false){
var valueToFind = "hi";
  var rounds = array.length;
  if (rounds < 0){
  return false
  }
  if (array[rounds] == valueToFind){
  done = true
    return rounds
  }
  rounds = rounds - 1
}
Posted by: Guest on November-23-2020

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