javascript indexOf object value in array
// Get index of object with specific value in array
const needle = 3; // needle
const haystack = [{ id: 1 }, { id: 2 }, { id: 3 }]; // haystack
const index = haystack.findIndex(item => item.id === needle);
javascript indexOf object value in array
// Get index of object with specific value in array
const needle = 3; // needle
const haystack = [{ id: 1 }, { id: 2 }, { id: 3 }]; // haystack
const index = haystack.findIndex(item => item.id === needle);
using index of on array of objects
arr = [{x: "a", y: 1}, {x: "something", y: 2}]
arr.findIndex(obj => obj.x === "a" && obj.y === 1);
javascript findindex
const array1 = [5, 12, 8, 130, 44];
const search = element => element > 13;
console.log(array1.findIndex(search));
// expected output: 3
const array2 = [
{ id: 1, dev: false },
{ id: 2, dev: false },
{ id: 3, dev: true }
];
const search = obj => obj.dev === true;
console.log(array2.findIndex(search));
// expected output: 2
findindex js
// findIndex(callback fn)
// .... return index (when condition meets)
// .... return -1 (if condition not meets)
const array = [5, 12, 8, 130, 44];
/// it returns the index of number which satisfy the condition true
const index = array.findIndex((item)=> item>10); //1
/// now we can check what element at that index...
console.log(array[index]); // array[1]
get the index of object in array
var elementPos = array.map(function(x) {return x.id; }).indexOf(idYourAreLookingFor);
var objectFound = array[elementPos];
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