Answers for "binary representation javascript"

2

how to get binary value of int javascript

const convertNumberToBinary = number => {
    return (number >>> 0).toString(2);
}
Posted by: Guest on May-28-2020
3

javascript convert number to binary representation

// Javascript convert a number to a binary equivalent.
// Syntax: n.toString(radix)
// Note that radix in this syntax is the radix n will become.
let n = 100;
let binary = n.toString(2);
// => 1100100

// Convert a binary number to a radix of 10 equivalent.
// Syntax: parseInt(num, radix).
// Note that radix in this syntax is denoting i's current radix.
let i = 1100100;
let number = parseInt(i, 2);
// => 100
Posted by: Guest on March-05-2020
5

binaryserachindex javascript

function binarySearchIndex (array, target, low = 0, high = array.length - 1) {
  if (low > high) {
    return -1
  }
  const midPoint = Math.floor((low + high) / 2)

  if (target < array[midPoint]) {
    return binarySearchIndex(array, target, low, midPoint - 1)
  } else if (target > array[midPoint]) {
    return binarySearchIndex(array, target, midPoint + 1, high)
  } else {
    return midPoint
  }
}
Posted by: Guest on April-08-2020
2

javascript convert to and from binary

/* From decimal to binary (similar fo rother base) */
const num = 7;
num.toString(2); // output: "111"

/* From binary (similar fo rother base) to decimal */
parseInt("111", 2); // output: 7
Posted by: Guest on May-21-2020
0

number to binary javascript

// method one
function convertNumberToBinary (num) {
 return parseInt([...num.toString(2)].reverse().join(''), 2);
}

// methode two
function convertNumberToBinary (num) {
 return parseInt(num.toString(2).slice('').reverse().join(''), 2);
}

// methode three
function convertNumberToBinary (num) {
  let binary = (n >>> 0).toString(2).split('').sort().join('');
  let number = parseInt(binary, 2);
  return num;
}
Posted by: Guest on June-23-2020
0

how to convert to binary in javascript

function bin(num) {
    var binn = [];
    var c;
    while (num != 1) {
        c = Math.floor(num / 2);
        binn.unshift(num % 2);
        num = c;

    }
    binn.unshift(1)
    return binn
}
//returns list of binary nos. in order
Posted by: Guest on September-08-2020

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