Answers for "sort array javascript object property"

5

typescript sort array of objects

const list = [
  { color: 'white', size: 'XXL' },
  { color: 'red', size: 'XL' },
  { color: 'black', size: 'M' }
]

list.sort((a, b) => (a.color > b.color) ? 1 : -1)
Posted by: Guest on June-15-2020
15

sort by object property javascript

let list = [
  {
      name: "world"
  },
  {
      name: "hello",
  },
];

// This doesn't account for if names are the same between objects
let x = list.sort((a, b) => (a.name > b.name ? 1 : -1));

console.log(x);

/*
[
  {
      name: "hello",
  },
  {
      name: "world"
  },
];
*/
Posted by: Guest on August-23-2020
17

javascript sort array of objects

const books = [
  {id: 1, name: 'The Lord of the Rings'},
  {id: 2, name: 'A Tale of Two Cities'},
  {id: 3, name: 'Don Quixote'},
  {id: 4, name: 'The Hobbit'}
]

compareObjects(object1, object2, key) {
  const obj1 = object1[key].toUpperCase()
  const obj2 = object2[key].toUpperCase()

  if (obj1 < obj2) {
    return -1
  }
  if (obj1 > obj2) {
    return 1
  }
  return 0
}

books.sort((book1, book2) => {
  return compareObjects(book1, book2, 'name')
})

// Result:
// {id: 2, name: 'A Tale of Two Cities'}
// {id: 3, name: 'Don Quixote'}
// {id: 4, name: 'The Hobbit'}
// {id: 1, name: 'The Lord of the Rings'}
Posted by: Guest on February-25-2020
7

sort array of objects by string property value

function compareFirstNames( a, b ) {
  if ( a.first_name < b.first_name ){
    return -1;
  }
  if ( a.first_name > b.first_name ){
    return 1;
  }
  return 0;
}

var people =[
    {"first_name":"Carol", "age":29},
    {"first_name":"Anna", "age":32},
    {"first_name":"Bob", "age":32}
];

people.sort( compareFirstNames ); //people is now sorted by first name from a-z
Posted by: Guest on July-22-2019
7

sort array of objects javascript by value

let orders = [
  { 
    order: 'order 1', date: '2020/04/01_11:09:05'
  },
  { 
    order: 'order 2', date: '2020/04/01_10:29:35'
  },
  { 
    order: 'order 3', date: '2020/04/01_10:28:44'
  }
];


console.log(orders);

orders.sort(function(a, b){
  let dateA = a.date.toLowerCase();
  let dateB = b.date.toLowerCase();
  if (dateA < dateB) 
  {
    return -1;
  }    
  else if (dateA > dateB)
  {
    return 1;
  }   
  return 0;
});

console.log(orders);
Posted by: Guest on April-01-2020
11

javascript sort array of object by property

function sortByDate( a, b ) {
  if ( a.created_at < b.created_at ){
    return -1;
  }
  if ( a.created_at > b.created_at ){
    return 1;
  }
  return 0;
}

myDates.sort(sortByDate);//myDates is not sorted.
Posted by: Guest on February-11-2020

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