Answers for "ajax get javascript"

7

jquery ajax get

$.ajax({
    	url: "www.site.com/page",
    	success: function(data){ 
    	    $('#data').text(data);
    	},
    	error: function(){
    		alert("There was an error.");
    	}
    });
Posted by: Guest on March-28-2020
2

ajax open a request

<script>
function loadDoc() {
  var xhttp = new XMLHttpRequest();
  
  //looking for a change or state , like a request or get.
  xhttp.onreadystatechange = function() {
     
     //if equal to 4 means that its ready.
    // if equal to 200 indicates that the request has succeeded.
    if (this.readyState == 4 && this.status == 200) {
      document.getElementById("demo").innerHTML = this.responseText;
    }
  };
  
  //GET method for gettin the data // the file you are requesting
  xhttp.open("GET", "TheFileYouWant.html", true);
  
  //sending the request
  xhttp.send();
}
Posted by: Guest on January-18-2020
2

ajax get js

let xhr = new XMLHttpRequest();

xhr.open("GET", "une/url");

xhr.responseType = "json";

xhr.send();

xhr.onload = function(){
    if (xhr.status != 200){ 
        alert("Erreur " + xhr.status + " : " + xhr.statusText);
    }else{ 
        alert(xhr.response.length + " octets  téléchargés\n" + JSON.stringify(xhr.response));
    }
};

xhr.onerror = function(){
    alert("La requête a échoué");
};

xhr.onprogress = function(event){
    if (event.lengthComputable){
        alert(event.loaded + " octets reçus sur un total de " + event.total);
    }
};
Posted by: Guest on April-14-2021
1

javascript ajax get

const xhttp = new XMLHttpRequest();
xhttp.onload = function() {
    document.getElementById("demo").innerHTML = this.responseText;
}
xhttp.open("GET", URL);
xhttp.send();
Posted by: Guest on August-05-2021

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