jquery ajax get
$.ajax({
url: "www.site.com/page",
success: function(data){
$('#data').text(data);
},
error: function(){
alert("There was an error.");
}
});jquery ajax get
$.ajax({
url: "www.site.com/page",
success: function(data){
$('#data').text(data);
},
error: function(){
alert("There was an error.");
}
});ajax get html response
//your jquery code will be like this:
$.ajax({
type: 'POST',
url: $url,
data: new FormData(this),
dataType: 'json',
contentType: false,
processData:false,//this is a must
success: function(response){
$('your_selector').html(response);
}
});
//php code will be like this
echo '<div>some html code</div>';
die();get json data in ajax call
<!doctype html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>jQuery.getJSON demo</title>
<style>
img {
height: 100px;
float: left;
}
</style>
<script src="https://code.jquery.com/jquery-3.5.0.js"></script>
</head>
<body>
<div id="images"></div>
<script>
(function() {
var flickerAPI = "https://api.flickr.com/services/feeds/photos_public.gne?jsoncallback=?";
$.getJSON( flickerAPI, {
tags: "mount rainier",
tagmode: "any",
format: "json"
})
.done(function( data ) {
$.each( data.items, function( i, item ) {
$( "<img>" ).attr( "src", item.media.m ).appendTo( "#images" );
if ( i === 3 ) {
return false;
}
});
});
})();
</script>
</body>
</html>Copyright © 2021 Codeinu
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