ajax request in javascript
fetch('https://api.covid19api.com/summary')
.then(response => response.json())
.then(data => console.log(data))
.catch(err => {
console.log(err)
});ajax request in javascript
fetch('https://api.covid19api.com/summary')
.then(response => response.json())
.then(data => console.log(data))
.catch(err => {
console.log(err)
});ajax syntax in javascript
var id = empid;
$.ajax({
type: "POST",
url: "../Webservices/EmployeeService.asmx/GetEmployeeOrders",
data: "{empid: " + empid + "}",
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function(result){
alert(result.d);
console.log(result);
}
});how to make ajax request javascript
//Change the text of a <div> element using an AJAX //request:
//using JQuery
$("button").click(function(){
$.ajax({url: "demo_test.txt", success: function(result){
$("#div1").html(result);
}});
});
//To send a request to a server, we use the open() //and send() methods of the XMLHttpRequest object:
// Javascript
xhttp.open("GET", "ajax_info.txt", true);
xhttp.send();
//example below
<html>
<body>
<h1>The XMLHttpRequest Object</h1>
<button type="button" onclick="loadDoc()">Request data</button>
<p id="demo"></p>
<script>
function loadDoc() {
var xhttp = new XMLHttpRequest();
xhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
document.getElementById("demo").innerHTML = this.responseText;
}
};
xhttp.open("GET", "demo_get.asp", true);
xhttp.send();
}
</script>
</body>
</html>ajax open a request
<script>
function loadDoc() {
var xhttp = new XMLHttpRequest();
//looking for a change or state , like a request or get.
xhttp.onreadystatechange = function() {
//if equal to 4 means that its ready.
// if equal to 200 indicates that the request has succeeded.
if (this.readyState == 4 && this.status == 200) {
document.getElementById("demo").innerHTML = this.responseText;
}
};
//GET method for gettin the data // the file you are requesting
xhttp.open("GET", "TheFileYouWant.html", true);
//sending the request
xhttp.send();
}js ajax
// For a plain JS solution, use these functions:
function _GET_REQUEST(url, response) {
var xhttp;
if (window.XMLHttpRequest) {
xhttp = new XMLHttpRequest();
} else {
xhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
response(this.responseText);
}
};
xhttp.open("GET", url, true);
xhttp.send();
}
function _POST_REQUEST(url, params, response) {
var xhttp;
if (window.XMLHttpRequest) {
xhttp = new XMLHttpRequest();
} else {
xhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
response(this.responseText);
}
};
xhttp.open("POST", url, true);
xhttp.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
xhttp.send(params);
}
// and apply like this:
_GET_REQUEST('http://someurl', (response) => {
// do something with variable response
});
_POST_REQUEST('http://someurl', 'paramx=y', (response) => {
// do something with variable response
});Copyright © 2021 Codeinu
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