Answers for "ajax function call in javascript"

5

ajax call

$.ajax({
        url: "Url",
        dataType: "json",
        type: "Post",
        async: true,
        data: {"Key":value,"Key2":value2},
        success: function (data) {
                
        },
        error: function (xhr, exception, thrownError) {
            var msg = "";
            if (xhr.status === 0) {
                msg = "Not connect.\n Verify Network.";
            } else if (xhr.status == 404) {
                msg = "Requested page not found. [404]";
            } else if (xhr.status == 500) {
                msg = "Internal Server Error [500].";
            } else if (exception === "parsererror") {
                msg = "Requested JSON parse failed.";
            } else if (exception === "timeout") {
                msg = "Time out error.";
            } else if (exception === "abort") {
                msg = "Ajax request aborted.";
            } else {
                msg = "Error:" + xhr.status + " " + xhr.responseText;
            }
            if (callbackError) {
                callbackError(msg);
            }
           
        }
    });
Posted by: Guest on January-06-2021
3

ajax request in javascript

fetch('https://api.covid19api.com/summary')
            .then(response => response.json())
            .then(data => console.log(data))
            .catch(err => {
                console.log(err)
            });
Posted by: Guest on May-19-2021
6

ajax syntax in javascript

var id = empid;

$.ajax({
    type: "POST",
    url: "../Webservices/EmployeeService.asmx/GetEmployeeOrders",
    data: "{empid: " + empid + "}",
    contentType: "application/json; charset=utf-8",
    dataType: "json",
    success: function(result){
        alert(result.d);
        console.log(result);
    }
});
Posted by: Guest on September-30-2020

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