ajax request in javascript
fetch('https://api.covid19api.com/summary')
.then(response => response.json())
.then(data => console.log(data))
.catch(err => {
console.log(err)
});
ajax request in javascript
fetch('https://api.covid19api.com/summary')
.then(response => response.json())
.then(data => console.log(data))
.catch(err => {
console.log(err)
});
ajax syntax in javascript
var id = empid;
$.ajax({
type: "POST",
url: "../Webservices/EmployeeService.asmx/GetEmployeeOrders",
data: "{empid: " + empid + "}",
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function(result){
alert(result.d);
console.log(result);
}
});
how to make ajax request javascript
//Change the text of a <div> element using an AJAX //request:
//using JQuery
$("button").click(function(){
$.ajax({url: "demo_test.txt", success: function(result){
$("#div1").html(result);
}});
});
//To send a request to a server, we use the open() //and send() methods of the XMLHttpRequest object:
// Javascript
xhttp.open("GET", "ajax_info.txt", true);
xhttp.send();
//example below
<html>
<body>
<h1>The XMLHttpRequest Object</h1>
<button type="button" onclick="loadDoc()">Request data</button>
<p id="demo"></p>
<script>
function loadDoc() {
var xhttp = new XMLHttpRequest();
xhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
document.getElementById("demo").innerHTML = this.responseText;
}
};
xhttp.open("GET", "demo_get.asp", true);
xhttp.send();
}
</script>
</body>
</html>
js ajax receive html
$.ajax({
type: 'POST',
url: "<Your URL>",
contentType: 'application/json; charset=utf-8'
// Set your dataType to either 'html' or 'text'.
// Keep in mind: dataType is for receiving,
// contentType is for sending
dataType: 'html',
data: { example: 1, id: "0x100"},
// Note: the data above is used in sending,
// data below is a variables that stores received data
success: function (data){
// Suppose you have an html element, where you want to append
// the response:
$('#<Your html element id>').html(data);
// .html(data) overwrites existing data
// Use .append(data) to add response without overwriting!
}
});
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