Answers for "js fibonacci recursive"

2

javascript recursive fibonacci

// Recursion way to return Fibonacci numbers
function recursiveFibonacci(n){
	// base case
	if(n === 0) return 0
  	if(n === 1) return 1
  
  	// recursioin base
  	return recursiveFibonacci(n - 2) + recursiveFibonacci(n - 1);
}
recursiveFibonacci(6) // should return 8

//////// and ////////

// Iteration way to return Fibonacci numbers
function iterativeFibonacci(n) {
  if (n === 0) return 0;
  if (n === 1) return 1;

  let previous = 0;
  let current = 1;
  for (let i = n; i > 1; i--) {
    let next = previous + current;
    previous = current;
    current = next;
  }
  return current;
}

iterativeFibonacci(6) // should return 8
Posted by: Guest on February-11-2021
0

fibonacci best performance javascript

// A sequência começa com 0 e 1, depois,
// os números subsequentes são compostos
// pela soma dos dois números anteriores
// da sequência. Daí:
// (x - 2) + (x - 1) = próximo número da sequência
function fibonacci(n) {
	const list = [0, 1];
	for (let x = 2; x < n + 1; x += 1) {
		list.push(list[x - 2] + list[x - 1]);
	}
	return list[n];
}

console.log(fibonacci(4));
Posted by: Guest on May-28-2020
0

recursive function for fibonacci series in java javascript

var fib = function(n) {
  if (n === 1) {
    return [0, 1];
  } else {
    var arr = fib(n - 1);
    arr.push(arr[arr.length - 1] + arr[arr.length - 2]);
    return arr;
  }
};

console.log(fib(8));
Posted by: Guest on May-08-2020
0

fibonacci sums javascript

// Implement a method that finds the sum of the first n
// fibonacci numbers recursively. Assume n > 0

function fibsSum(n) {
    if ( n === 1 ) {
        return 1;
    }
    if (n === 2 ) {
        return 2;
    }
    let sum = fibsSum(n-1) + n;
    return sum;
}
Posted by: Guest on October-24-2020

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