Answers for "async () => {"

4

javascript async function

// Old School Javascript Invoke
(async function() {
	await someAsyncFunction();
})();

//New ES6 Javascript Invoke
(async () => {
	await someAsyncFunction();
})();
Posted by: Guest on September-26-2021
2

async await

async function f() {

  try {
    let response = await fetch('/no-user-here');
    let user = await response.json();
  } catch(err) {
    // catches errors both in fetch and response.json
    alert(err);
  }
}

f();
Posted by: Guest on June-18-2020
3

async

function resolveAfter2Seconds() {
  return new Promise(resolve => {
    setTimeout(() => {
      resolve('resolved');
    }, 2000);
  });
}

async function asyncCall() {
  console.log('calling');
  const result = await resolveAfter2Seconds();
  console.log(result);
  // expected output: 'resolved'
}

asyncCall();
Posted by: Guest on May-29-2020
0

async await

// ASYNC will always returns promises
// NOTE : AWAIT should be kept only inside ASYNC function
// AWAIT can't be used in regular function
/* TIPS : Js is single threaded & synchronous in nature BUT, we can
          make it as asyncronous by using (ASYNC/AWAIT)*/

//(Example 1 : fetching Random Image)
async function RandomImage(){  //remember async and await is powerful for async operations, always await should be inside of async only.

  try {
    const raw_response = await fetch("https://www.themealdb.com/api/json/v1/1/random.php");
      if (!raw_response.ok) { // check for the 404 errors
          throw new Error(raw_response.status);
      }
    const json_data = await raw_response.json();  //AWAIT
    let data = json_data.meals[0];

    console.log(data);
  }
  catch (error) { // catch block for network errors
      console.log(error); 
  }
}
RandomImage();


//(Example 2 : returning another promise)
console.log("1 is working");
console.log("2 is working");
  var AsyncFunction = async() => {
    var x = new Promise((resolve,reject) => {
        setTimeout(() => resolve("3 is working"), 3000);
    });
    var result = await x;
    return result;
  }
AsyncFunction().then(resolved => console.log(resolved));
console.log("3 is working");
Posted by: Guest on December-16-2020

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