Answers for "fetch async await example"

12

async function fetchJson

async function getUserAsync(name) 
{
  let response = await fetch(`https://api.github.com/users/${name}`);
  let data = await response.json()
  return data;
}

getUserAsync('yourUsernameHere')
  .then(data => console.log(data));
Posted by: Guest on February-16-2020
9

async fetch api call

async function getUserAsync(name) {
  try{
    let response = await fetch(`https://api.github.com/users/${name}`);
    return await response.json();
  }catch(err){
    console.error(err);
    // Handle errors here
  }
}
Posted by: Guest on March-04-2020
13

js async await

/* Notes:
	1. written like synchronous code
    2. compatible with try/catch blocks
    3. avoids chaining .then statements
    4. async functions always return a promise
    5. function pauses on each await expression
    6. A non promise value is converted to 
       Promise.resolve(value) and then resolved
*/

// Syntax
// Function Declaration
async function myFunction(){
  await ... // some code goes here
}
  
// Arrow Declaration
const myFunction2 = async () => {
  await ... // some code goes here
}
  
 // OBJECT METHODS

const obj = {
	async getName() {
		return fetch('https://www.example.com');
	}
}

// IN A CLASS

class Obj {
	// getters and setter CANNOT be async
	async getResource {
		return fetch('https://www.example.com');
	}
}
Posted by: Guest on February-25-2020
0

async and await

function delayResult() {
 return new Promise(resolve => {
   setTimeout(() => {
     resolve(‘Done’);
   }, 5000)
 })
}
async function getResult() {
 let result = await delayResult();
 return result;
}
getResult();
Posted by: Guest on November-26-2020

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