get an array with unique values
function onlyUnique(value, index, self) {
return self.indexOf(value) === index;
}
// usage example:
var a = ['a', 1, 'a', 2, '1'];
var unique = a.filter(onlyUnique);
console.log(unique); // ['a', 1, 2, '1']
get an array with unique values
function onlyUnique(value, index, self) {
return self.indexOf(value) === index;
}
// usage example:
var a = ['a', 1, 'a', 2, '1'];
var unique = a.filter(onlyUnique);
console.log(unique); // ['a', 1, 2, '1']
unique numbers in array
import java.util.ArrayList;
public class UniqueNumbersInArray {
public static void main(String[] args) {
int arr[] = { 4,5,5,4,5,6,5,8,4,7};
ArrayList<Integer> uniqueArr = new ArrayList<Integer>();
for (int i = 0; i < arr.length; i++) {
int k = 0;
if (!uniqueArr.contains(arr[i])){
uniqueArr.add(arr[i]);
k++;
for (int j = i; j < args.length ; j++) {
if (arr[i]==arr[j]){
k++;
}
}
System.out.println(arr[i]);
System.out.println(k);
}
}
}
}
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