Answers for "how to filter unique values in array javascript"

javascript array unique values

var arr = [55, 44, 65,1,2,3,3,34,5];
var unique = [...new Set(arr)]

//just  var unique = new Set(arr) wont be an array

how to find unique elements in array in javascript

let a = ["1", "1", "2", "3", "3", "1"];
let unique = a.filter((item, i, ar) => ar.indexOf(item) === i);
console.log(unique);

get unique array javascript

// one liner solution to get a unique array by object id
[{_id: 10},{_id: 20}, {_id: 20}].filter((item, i, ar) => ar.findIndex(each => each._id === item._id) === i)

Filtering an array for unique values

const my_array = [1, 2, 2, 3, 3, 4, 5, 5]
const unique_array = [...new Set(my_array)];
console.log(unique_array); // [1, 2, 3, 4, 5]

unique elements in array javascript

var array3 = [1, 2, 4, 6, 1, 4, 9, 10, 2, 8];
function findUniqueElements_3(array) {

    for (let i = 0; i < array.length; i++) {
        for (let j = i + 1; j < array.length; j++) {
            if (array[i] == array[j]) {
                array.splice(j, 1)
            }

        }
    }
    console.log(`from third way : ${array}`);
}

findUniqueElements_3(array3)