how to find unique elements in array in javascript
let a = ["1", "1", "2", "3", "3", "1"];
let unique = a.filter((item, i, ar) => ar.indexOf(item) === i);
console.log(unique);how to find unique elements in array in javascript
let a = ["1", "1", "2", "3", "3", "1"];
let unique = a.filter((item, i, ar) => ar.indexOf(item) === i);
console.log(unique);javascript find unique values in array
// usage example:
var myArray = ['a', 1, 'a', 2, '1'];
var unique = myArray.filter((v, i, a) => a.indexOf(v) === i);
// unique is ['a', 1, 2, '1']javascript get unique elements in array
function toUniqueArray(a){
var newArr = [];
for (var i = 0; i < a.length; i++) {
if (newArr.indexOf(a[i]) === -1) {
newArr.push(a[i]);
}
}
return newArr;
}
var colors = ["red","red","green","green","green"];
var colorsUnique=toUniqueArray(colors); // ["red","green"]unique numbers in array
import java.util.ArrayList;
public class UniqueNumbersInArray {
public static void main(String[] args) {
int arr[] = { 4,5,5,4,5,6,5,8,4,7};
ArrayList<Integer> uniqueArr = new ArrayList<Integer>();
for (int i = 0; i < arr.length; i++) {
int k = 0;
if (!uniqueArr.contains(arr[i])){
uniqueArr.add(arr[i]);
k++;
for (int j = i; j < args.length ; j++) {
if (arr[i]==arr[j]){
k++;
}
}
System.out.println(arr[i]);
System.out.println(k);
}
}
}
}Copyright © 2021 Codeinu
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