fetch api javascript
fetch('http://example.com/songs')
.then(response => response.json())
.then(data => console.log(data))
.catch(err => console.error(err));fetch api javascript
fetch('http://example.com/songs')
.then(response => response.json())
.then(data => console.log(data))
.catch(err => console.error(err));how to use fetch() javascript
//Most API's will only allow you to fetch on their website.
//This means you couldn't run this code in the console on
// google.com because:
// 1. Google demands the fetch request be from https
// 2. open-notify's API blocks the request outside of their website
fetch('http://api.open-notify.org/astros.json')
.then(function(response) {
return response.json();
})
.then(function(json) {
console.log(json)
});
// Here is another example. A method (function) that
// grabs Game of Thrones books from an API ...
function fetchBooks() {
return fetch('https://anapioficeandfire.com/api/books')
.then(resp => resp.json())
.then(json => renderBooks(json));
}
function renderBooks(json) {
const main = document.querySelector('main')
json.forEach(book => {
const h2 = document.createElement('h2')
h2.innerHTML = `<h2>${book.name}</h2>`
main.appendChild(h2)
})
}
document.addEventListener('DOMContentLoaded', function() {
fetchBooks()
})fetch in javascript
// Fetching random users
const getRandomUsers = n => {
console.log('---- Random users generated ---');
const fetchRandomUsers = fetch(`https://randomuser.me/api/?results=${n}`);
fetchRandomUsers.then( data => data.json().then( randomUsers => {
console.log(JSON.stringify(randomUsers.results.length));
randomUsers.results.forEach( randomUserGenerated => {
const{gender , email , name} = randomUserGenerated;
const {title , first , last } = name ;
let fullNames = `${title}.${first} ${last}`;
console.log(`${fullNames} -- ${gender} -- ${email}`);
})
}));
}
getRandomUsers(100);Copyright © 2021 Codeinu
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