preview image file upload javascript
<input type="file" accept="image/*" onchange="loadFile(event)">
<img id="output"/>
<script>
var loadFile = function(event) {
var output = document.getElementById('output');
output.src = URL.createObjectURL(event.target.files[0]);
output.onload = function() {
URL.revokeObjectURL(output.src) // free memory
}
};
</script>jquery upload image
$(document).ready(function (e) {
$('#imageUploadForm').on('submit',(function(e) {
e.preventDefault();
var formData = new FormData(this);
$.ajax({
type:'POST',
url: $(this).attr('action'),
data:formData,
cache:false,
contentType: false,
processData: false,
success:function(data){
console.log("success");
console.log(data);
},
error: function(data){
console.log("error");
console.log(data);
}
});
}));
$("#ImageBrowse").on("change", function() {
$("#imageUploadForm").submit();
});
});how to display image before upload in jhtml
function display(input) {
if (input.files && input.files[0]) {
var reader = new FileReader();
reader.onload = function(event) {
$('#myid').attr('src', event.target.result);
}
reader.readAsDataURL(input.files[0]);
}
}
$("#demo").change(function() {
display(this);
});Copyright © 2021 Codeinu
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