Answers for "blob javascript"

2

url to blob js

fetch('https://upload.wikimedia.org/wikipedia/commons/7/77/Delete_key1.jpg')
  .then(res => res.blob()) // Gets the response and returns it as a blob
  .then(blob => {
    // Here's where you get access to the blob
    // And you can use it for whatever you want
    // Like calling ref().put(blob)

    // Here, I use it to make an image appear on the page
    let objectURL = URL.createObjectURL(blob);
    let myImage = new Image();
    myImage.src = objectURL;
    document.getElementById('myImg').appendChild(myImage)
});
Posted by: Guest on April-30-2020
0

javascript create blob or data/image from image url

function convertImgToBase64URL(url, callback, outputFormat){
    var img = new Image();
    img.crossOrigin = 'Anonymous';
    img.onload = function(){
        var canvas = document.createElement('CANVAS'),
        ctx = canvas.getContext('2d'), dataURL;
        canvas.height = img.height;
        canvas.width = img.width;
        ctx.drawImage(img, 0, 0);
        dataURL = canvas.toDataURL(outputFormat);
        callback(dataURL);
        canvas = null; 
    };
    img.src = url;
}
convertImgToBase64URL('http://upload.wikimedia.org/wikipedia/commons/4/4a/Logo_2013_Google.png', function(base64Img){
alert('it works');
      $('.output').find('img').attr('src', base64Img);  
   
});


//function convertImgToBase64URL will convert the image into data url
Posted by: Guest on September-21-2020
8

what is a blob in javascript

//The Blob() constructor returns a new Blob object. The content of the blob
//consists of the concatenation of the values given in the parameter array.

//syntax
var newBlob = new Blob(array, options);
Posted by: Guest on August-18-2021
0

blob to text javascript

<RESPONSE PROMISE>
.then(r=>r.blob())
.then(r=>{
console.log(r.type)
return new Response(r)
})
.then(r=>
 r.text()
)
.then(console.log)
Posted by: Guest on April-26-2020
0

upload bloob javascript

var fd = new FormData();
fd.append('fname', 'test.wav');
fd.append('data', soundBlob);
$.ajax({
    type: 'POST',
    url: '/upload.php',
    data: fd,
    processData: false,
    contentType: false
}).done(function(data) {
       console.log(data);
});
Posted by: Guest on September-30-2020
-1

javascript blob

(() => {
 try {
  return !!new Blob();
 } catch (e) {
  return false;
 }
})()
Posted by: Guest on August-11-2021

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