multiply arrays javascript
var sum = 0;
for(var i=0; i< arr1.length; i++) {
sum += arr1[i]*arr2[i];
}multiply arrays javascript
var sum = 0;
for(var i=0; i< arr1.length; i++) {
sum += arr1[i]*arr2[i];
}javascript multiply array with scalar
var input = [3, 6, 4];
var scalar = 5;
var output = input.map(x => x * scalar); // [15, 30, 20]multiply function javascript
// MULTIPLY FUNCTION
const multiply = (num1, num2) => {
return num1 * num2;
};
let resulMultiply = multiply(4, 5);
console.log(resulMultiply);
// 20multiply js
const multiply = (x,y)=>{
if(x==1){ return y;}
else if(x>1){
return y +multiply(x-1,y)
}
else throw "Not Numbers"
}
var result = multiply(4,3);
console.log(result)multiply all numbers in an array javascript
The cause is already known. Here's an alternative - using Array.reduce for your method:
console.log( [1, 2, 3].reduce( (a, b) => a * b ) );
console.log( Array.from( {length: 20} )
.map( (v, i) => i + 1 )
.reduce( (a,b) => a * b )
.toLocaleString());
// for empty arrays, use some initial value
const arr = [];
if (arr.reduce( (a, b) => a * b, -1 ) === -1) {
console.error(`The given array ${arr} is empty`);
}Copyright © 2021 Codeinu
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