javascript add nd st th to number
function ordinal(number) { const english_ordinal_rules = new Intl.PluralRules("en", { type: "ordinal" }); const suffixes = { one: "st", two: "nd", few: "rd", other: "th" } const suffix = suffixes[english_ordinal_rules.select(number)]; return (number + suffix); } ordinal(3); /* output: 3rd */ ordinal(111); /* output: 111th */ ordinal(-1); /* output: -1st */
add st nd rd th javascript
The rules are as follows: 1. st is used with numbers ending in 1 (e.g. 1st, pronounced first) 2. nd is used with numbers ending in 2 (e.g. 92nd, pronounced ninety-second) 3. rd is used with numbers ending in 3 (e.g. 33rd, pronounced thirty-third) Note* : As an exception to the above rules, all the "teen" numbers ending with 11, 12 or 13 use -th (e.g. 11th, pronounced eleventh, 112th, pronounced one hundred [and] twelfth) th is used for all other numbers (e.g. 9th, pronounced ninth). The following JavaScript code (rewritten in Jun '14) accomplishes this: function ordinal_suffix_of(i) { var j = i % 10, k = i % 100; if (j == 1 && k != 11) { return i + "st"; } if (j == 2 && k != 12) { return i + "nd"; } if (j == 3 && k != 13) { return i + "rd"; } return i + "th"; }
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